문제)A 0.900V potential difference is maintained across a 1.50m length of tungsten wire that has a cross-sectional area of 0.600mm^2. Calculate the current in the wire. 풀이)l = 1.50mA = 0.600mm^2 = 0.600 × 10^-6 m^2 = 6.00 × 10^-7 m^2△V = 0.900 V V = IR, I = V / R, R = ρ × l ÷ A임을 이용함. tungsten의 ρ(resistivity) = 5.6 × 10^-8 I = V / R = ( V × A ) / ( ρ × l ) I = ( V × A ) / ( ρ × l ) = ( 0.900 V × ..